In Problems 35 and 36 find the point where the graph of f cr

In Problems 35 and 36, find the point where the graph of f crosses its slant asymptote. Use a graphing utility to obtain the graph of f and the slant asymptote in the same coordinate plane. f(x) = x^3 - 3x^2 + 2x/x^2 + 1 f(x) = x^3 + 2x - 4/x^2

Solution

f(x)= (x³+2x-4)/x²

Slant asymptote is y=x

(x³+2x-4)/x²=x

x³+2x-4=x³

2x-4=0

x=2

At x=2,f(x)= (2³+2*2-4)/(2²)= 4

Point is (2,4)