Anderson University CHE 1 rning nderson UniversityCHE 107Spr

Anderson University -CHE 1 rning nderson University-CHE 107-Spring18-PERDUN > Activities and Due Dates HW Score 02/26/2018 11:59 PM 068.1/100 Gradeboo Question 26 of 38 Sapling Learning Aa,8 mel sarmole o a of 397 mL. How many moles of Kir are in a 6.03 L sample at the same temperature and pressure? Previs MacBook Air 80 F2 -, F6

Solution

by using the avagadros law V1/n1=V2/n2 or n2=V2*n1/V1

here V1= 397 mL =0.397 L ; n1=1.6 mol ; V2= 6.03 L

using the values

n2= 6.03*1.6/0.397= 24.30 moles