2How many grams of ammonium nitrate are needed to be added i

2.How many grams of ammonium nitrate are needed to be added into 45.0mL of DI water in

order to make a 1.1 molal solution? (assume water density 1g/mL)

i got 3.6g does it make sense?

thank you

molar mass of ammonium nitrate = 80 g/mol

for 1.1 molal solution = 1.1 mole/ 1000 g

thus for 45.0 mL/ 50 g (as density of water is 1g/mL) of DI water we will need = 45.0*1.1/1000 mol

= 0.0495 mol

thus grams of ammonium nitrate = 0.0495 * 80 = 3.96 g