Write a function template sort that takes two references to

Write a function template sort that takes two references to generic objects and switches them if the first argument is larger than the second. It is only assumed that operator<() and a default constructor are defined for the objects considered.

Solution

main.cpp

#include <iostream>
using namespace std;

template <typename T>
void templateSort(T &n1, T &n2)
{
   T temp;
   temp = n1;
   n1 = n2;
   n2 = temp;
}

int main()
{
   int i1,i2;
   cout<<\"Enter two integer : \";
   cin>>i1>>i2;
   cout<<endl;
   cout << \"Before passing data to function template.\ \";
   cout << \"i1 = \" << i1 << \"\ i2 = \" << i2;
   if(i1>i2){
   templateSort(i1, i2);
   }
  
        cout << \"\ \ After passing data to function template.\ \";
   cout << \"i1 = \" << i1 << \"\ i2 = \" << i2;
  
   return 0;
}

Output:-