Use a table of integrals to evaluate and solve this problem

Use a table of integrals to evaluate and solve this problem. The region bounded by the graph of y=(1/(x+13)) and the x-axis on the interval [0,4] is revolved about the x-axis. What is the volume of the solid this is formed?

Solution

dv = pi* 1/(x+13)^2 dx dv = -pi/(x + 13) from x = 0 to x=4 : pi[ 1/13 - 1/17 ] 4pi/221 cubic units !!
Use a table of integrals to evaluate and solve this problem. The region bounded by the graph of y=(1/(x+13)) and the x-axis on the interval [0,4] is revolved ab

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