If tan theta 78 pi Solutiontanopposite sideadjacent side78
If tan theta = 7/8, pi
Solution
tan=opposite side/adjacent side=7/8 ,<<3/2
hypotenuse2=opposite side2+ adjacent side2
hypotenuse2=72+ 82
hypotenuse=113
sin =opposite side/hypotenuse= -7/113
cos =adjacent side/hypotenuse= -8/113
a)
sin(2)=2sincos
sin(2)=2(-7/113)(-8/113)
sin(2)=112/113
b)
cos(2)=1-2sin2
cos(2)=1-2(-7/113)2
cos(2)=1-(98/113)
cos(2)=(15/113)
c)sin(/2)=[(1-cos)/2]
sin(/2)=[(1-(-8/113))/2]
sin(/2)=[(113 +8)/2113]
d)cos(/2)=-[(1+cos)/2]
cos(/2)=-[(1+(-8/113))/2]
cos(/2)=-[(113 -8)/2113]
