If tan theta 78 pi Solutiontanopposite sideadjacent side78

If tan theta = 7/8, pi

Solution

tan=opposite side/adjacent side=7/8 ,<<3/2

hypotenuse2=opposite side2+ adjacent side2

hypotenuse2=72+ 82

hypotenuse=113

sin =opposite side/hypotenuse= -7/113

cos =adjacent side/hypotenuse= -8/113

a)

sin(2)=2sincos

sin(2)=2(-7/113)(-8/113)

sin(2)=112/113

b)

cos(2)=1-2sin2

cos(2)=1-2(-7/113)2

cos(2)=1-(98/113)

cos(2)=(15/113)

c)sin(/2)=[(1-cos)/2]

sin(/2)=[(1-(-8/113))/2]

sin(/2)=[(113 +8)/2113]

d)cos(/2)=-[(1+cos)/2]

cos(/2)=-[(1+(-8/113))/2]

cos(/2)=-[(113 -8)/2113]

 If tan theta = 7/8, pi Solutiontan=opposite side/adjacent side=7/8 ,<<3/2 hypotenuse2=opposite side2+ adjacent side2 hypotenuse2=72+ 82 hypotenuse=113 si

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