Solve the following exponent equation by expressing each sid
Solution
Lets bring the base to 2, and then equate RHS and LHS:
16^x+4 = 256^x-6
2^4(x+4) = 2^8(x-6)
4x+16 = 8x-48
64 = 4x
x=16
So. x=16

Lets bring the base to 2, and then equate RHS and LHS:
16^x+4 = 256^x-6
2^4(x+4) = 2^8(x-6)
4x+16 = 8x-48
64 = 4x
x=16
So. x=16
