U Exel to graph the data for diethyl ether as In vp v IT Ske

U Exel to graph the data for diethyl ether as In v.p. v. I/T. Sketch the graph below kilojoules per mole for this AND use the formula of the line to calculate the standard enthalpy of vaporization in compound. Be sure to convert temperature to Kelvin and itself) 146 231 531 15 Answer

Solution

Prepare a table on ln v.p. vs 1/T as below.

v.p. (mmHg)

146

231

355

531

T (°C)

-5

5

15

25

T (K)

(-5 + 273) = 268

(5 + 273) = 278

(15 + 273) = 288

(25 + 273) = 298

ln v.p.

4.9836

5.4424

5.8721

6.2748

1/T (K^-1)

0.00373

0.00360

0.00347

0.00335

Plot ln v.p. vs 1/T as below.

Plot on ln v.p. vs 1/T (K^-1)

The regression equation is y = -3388.9x + 17.631 ……(1)

Since x has the unit 1/K and the left side is dimensionless, hence, the slope of the plot is -3388.9 K.

The integrated form of the Clasius-Clapeyeron equation is

ln v.p. = -H_v/R*(1/T) + C …….(2)

Comparing (1) and (2), we must have

-H_v/R = -3388.9 K

====> H_v = (3388.9 K)*R = (3388.9 K)*(8.314 J/mol.K)*(1 kJ/1000 J) = (28175.3146 J/mol)*(1 kJ/1000 J) = 28.1753146 kJ/mol 28.1753 kJ/mol (ans).

v.p. (mmHg)	146	231	355	531
T (°C)	-5	5	15	25
T (K)	(-5 + 273) = 268	(5 + 273) = 278	(15 + 273) = 288	(25 + 273) = 298
ln v.p.	4.9836	5.4424	5.8721	6.2748
1/T (K-1)	0.00373	0.00360	0.00347	0.00335