if 16 g ofaspirin were obtained from 16 g of salicylic acid

if 1.6 g ofaspirin were obtained from 1.6 g of salicylic acid by reaction with excess acetic anhydride, what would be the percentage yield? .

Solution

molar mass of aspirine = 180.157g/mol

moles of aspirine = 8.88*10^-3

molar mass of salicylic acid = 138.121 g/mol

moles of salicylic acid = 0.01158 moles

C7H6O3 + C4H6O3 ? C9H8O4 + CH3COOH

so moles of acetic acid = 0.01158 = 0.6948 g

yeild = 1.6/(1.6+0.6948) = 69.723 %