12 Consider the function fxyz x4y3z2 and the level surface
1.2) Consider the function f(x,y,z) = x^4y^3z^2 and the level surface of this function that passes through the point P0 = (1,1,3).
Find an equation for the tangent plane to the level surface of the given function at P0.
Find an equation for the tangent plane to the level surface of the given function at P0.
Solution
f(x,y,z) = x^4y^3z^2 = 4*3*6(x-1)^3(y-1)^2 (z - 3) = 72(x-1)^3(y-1)^2 (z - 3) equation of tangent