Zns 2AgNO3aq 2Ags ZnNO32aq When 162 g of silver was produ

Zn(s) + 2AgNO₃(aq) --> 2Ag(s) + Zn(NO₃)₂(aq)

When 16.2 g of silver was produced, _____ g of zinc nitrate would be produced.

Solution

moles of silver=16.2/108

=0.15

so moles of zn (NO3)2=0.15*0.5

=0.075

so mass of zince nitrate=0.075*189.36

=14.202 grams