The value of Ka for acetylsalicylic acid aspirin is 300104 W
The value of Ka for acetylsalicylic acid (aspirin) is 3.00×10-4. What is the value of Kb, for its conjugate base, C9H7O4-?
Solution
by definition
Ka x Kb = Kw = 1 x 10-14
Ka x Kb = 1 x 10-14
now
given Ka = 3 x 10-4
so
3 x 10-4 x Kb = 1 x 10-14
Kb = 3.333 x 10-11
so
the value of Kb is 3.333 x 10-11
