Leap years contain one additional day February 29 in order t

Leap years contain one additional day (February 29) in order to keep the calendar synchronized with the sun (because the earth revolves around the sun closer to once every 365.25 days). A year is a leap year if it is divisible by 4, unless it is a century (evenly divisible by 100) that is not divisible by 400. Note that 2015 is not a leap year, 1980 was a leap year, 2000 was a leap year, 1900 was not a leap year. Write a program that contains a user-defined function named is Leap Year, that takes a year value as an integer argument and returns true if the year is a leap year, false otherwise. Do not use the >> or

Solution

#include<iostream>
using namespace std;
bool isLeapYear(int year){
if ((year%4 == 0 && year%100 !=0)|| year%400 == 0)
   {
   return true;
}
   else
   {
   return false;
   }  
}
int main()
{
int year;
char ch=\'y\';
while(ch ==\'y\'||ch==\'Y\'){


cout<<\"Enter a year value: \";
cin >> year;
if(isLeapYear(year)){
cout<<year<<\" is a leap year\"<<endl;
}
else{
cout<<year<<\" is not a leap year\"<<endl;
}
cout<<\"Continue? (y/n): \";
cin >> ch;


}
return 0;
}

Output:

sh-4.2$ g++ -o main *.cpp                                                                                                                                                                                                                                                

sh-4.2$ main                                                                                                                                                                                                                                                             

Enter a year value: 2015                                                                                                                                                                                                                                                 

2015 is not a leap year                                                                                                                                                                                                                                                  

Continue? (y/n): y                                                                                                                                                                                                                                                       

Enter a year value: 2000                                                                                                                                                                                                                                                 

2000 is a leap year                                                                                                                                                                                                                                                      

Continue? (y/n): y                                                                                                                                                                                                                                                       

Enter a year value: 1900                                                                                                                                                                                                                                                 

1900 is not a leap year                                                                                                                                                                                                                                                  

Continue? (y/n): n