Solve the expression 2x32x2128x128 for its squareroot sSolut

Solve the expression 2x^3-2x^2-128x+128 for its squareroot s

Solution: The given expression is

2x^3-2x^2-128x+128

=2x^2(x-1)-128(x-1)

=(x-1)(2x^2-128)

=2(x-1)(x^2-64)

=2(x-1)(x+4)(x-4)

Therefore

The zeroes of the expression are

x = 1, 4, -4 <------------- Answer