QUESTION 2 Calculate the value of K for the reaction shown i

QUESTION 2 Calculate the value of K for the reaction shown if the image in the square represents equilibrium. N2(g) + O2(g) 2 NO(g) 0.17 0085 O 0.4

Solution

K = [NO]^2/[N2][O2]

Number of moles of NO at equilibrium = 2

Number of moles of N2 at equilibrium = 6

Number of moles of O2 at equilibrium = 4

K = 2^2 / (6*4)

K = 0.17

Answer option B) 0.17

 QUESTION 2 Calculate the value of K for the reaction shown if the image in the square represents equilibrium. N2(g) + O2(g) 2 NO(g) 0.17 0085 O 0.4 SolutionK =

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