3 Compare the alternatives shown below on the basis of their
Solution
ANSWER:
due to technical problem , cash flow diagrams pic couldn\'t be uploaded , so sorry for the diagram.
1) Alternative u : we need to find the amount through one life cycle.
a = initial investment(a/p,i,n) + annual cost + salvage value(a/f,i,n)
i = 14% and n = 5 years
a = -8,500,000(a/p,14%,5) - 8,000 + 5,000(a/f,14%,5)
a = -8,500,000 * 0.2913 - 8,000 + 5,000 * 0.1513
a = -2,476,050 - 8,000 + 756.5 = -$2,483,294
capitalized cost = a / i = -2,483,294 / 14% = -$17,737,810.7
2) alternative w
a = initial investment(a/p,i,n) + annual cost + salvage value(a/f,i,n)
i = 14% and n = infinity
a = -50,000,000(a/p,14%,infinity) - 7,000 + 2,000(a/f,14%,infinity)
a = -50,000,000 * 0.14 - 7,000 + 2,000 * 0
a = -7,000,000 - 7,000 + 0 = -$7,007,000
capitalized cost = a / i = -7,007,000 / 14% = -$50,050,000
so we select alternative u.
