The Business School at a fecal college offers eight sections

The Business School at a fecal college offers eight sections of basic statistics. students enrolled in those sections: 52. 28. 38. 32. 49. 29. 24 and 28 Calculate the range. Calculate the arithmetic mean.

Solution

Part a) Here formula for range is :

RAnge = Maximum value - Minimum value of the series

so in given series :

Range = 52 - 24 = 28             First answer.

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Part B) Here formula for mean is

Mean = Sum of all observations/total observations

=( 52+ 28+38+32+49+29+24+28) /8 = 280/8 = 35

So last arithemtic mean answer is 35.

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Part c) Here mean deviation is actually the mean of all the deviations of all values of series from its mean.

so first deviation = |52- 35 | = 17

second deviation = ||28-35| = 7

third deviation = | 38-35 |= 3                fourth deviation = |32- 35 | = 3

fifth deviation = | 49- 35 | = 14               sixth deviation = |29 - 35| = 6

seventh deviation = |24- 35| = 11            eigth deviation = |28- 35| = 7

So sum of all deviations = 17+7+3+14+11+3+6+7 = 68

So required mean deviation = sum of all deviations/mean = 68/35= 1.94          Answer

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Part d )

Thus range and mean deviation is interpretted as :

\" The difference between 52 and 24 is 28 . On the average of number of students enrolled deviates 1.94 from the mean 35.\"