Two forces of 423 N and 590 N act on an object The angle bet

Two forces of 423 N and 590 N act on an object. The angle between the forces is 48 degree. Find the magnitude of the resultant and the angle that it makes with the larger force. The magnitude of the resultant is approximately N. (Round to the nearest whole number as needed.)

Solution

Rx = 423 cos 0 + 590 cos 48

Rx = 817.787

Ry = 423 sin 0 + 590 sin 48

Ry = 438.455

R = sqrt ( 817.787^2 + 438.455^2 )

R = 927.91

therefore, magnitude of resultant force is 928 N

angle = tan^-1 ( 438.455 / 817.787)

= 28.198 degrees