Find the equation of a line that is perpendicular to the lin

Find the equation of a line that is perpendicular to the line y = 1/3 x + 3 and contains the point (-6, 0). y = (Type your answer in slope-intercept form.)

Solution

The slope of perpendicular lines are the negative reciprocals of each other, and a pair of these lines intersects at 90 degrees

thus M1 * M2 = -1

Given slope M1 = 1/3

So, M2 = -3

So, equation is

y = -3x + c

It passes through ( -6, 0)...Putting this in above equation

0 = -3 * -6 + c

c = -18

So, equation is :

y = -3x - 18