Use the unilateral ztransform UZT rather than the bilateral

Use the unilateral z-transform (UZT) rather than the bilateral z-transform (BZT) in this course. The BZT is defined as follows: F(z) = sigma^infinity_k = - infinity f[k]z^-k. Compute the BZT of f[k] = a^k u[k] and f[k] = -a^ku[-k - 1] and include the region of convergence in each case. Also, what is the UZT for each of these discrete-time signals?

Solution

#include<stdio.h>
#include<conio.h>

void Board();
void PlayerX();
void PlayerO();
void Player_win();
void check();
int win=0,wrong_X=0,wrong_O=0,chk=0;

char name_X[30];
char name_O[30];
int pos_for_X[3][3];
int pos_for_O[3][3];
int pos_marked[3][3];

void main()

               }
               printf(\"\ \ \");
               clrscr();
               printf(\"\ Enter the name of the player enjoying for \\\'X\\\': \");
               fflush(stdin);
               gets(name_X);
               printf(\"\ Enter the name of the player enjoying for \\\'O\\\': \");
               fflush(stdin);
               gets(name_O);
               Board();
               for(;;)
              
}
void PlayerO()