Flag Problem Help 4 A raffle is being held at a wheelchair b

Flag Problem Help 4. A raffle is being held at a wheelchair basketball game to raise money for new team uniforms. Exactly 171 raffle tickets were sold. For the raffle, 3 tickets will be drawn and a different prize awarded for each one. Bryant, Arturo, and Garrett each bought 12 tickets. What is the probability that Bryant will win first, then Arturo, and finally Garrett? 96 818,805 272,935 185,193 1,666,737 Back Next

Solution

3)

Dafna password contains 2 letters followed by 2 numerical digits.

All letters and numbers are different from each other and are not case senstive.

Total number of passwords that can be formed in this condition are :

26 * 25 * 10 * 9              //       26 letters are there for the first place, 25 letters for the second place, 10 numbers are for first numerical digit and 9 for the second digit.

so the probability of guesing right in first try = 1 / (26*25*10*9)

                                                                        = 1 / 58500                              

.

4)

Total number of raffle sold = 171

each one purchased 12 tickets.

3 tickets will be drawn and different prize will be rewarded for each one

Probability that Bryant will win first = tickets he purchased / total number of tickets

Probability that Bryant will win first = 12 / 171

Probability that Arturo will win Second = tickets he purchased / total number of tickets left      

Probability that Arturo will win Second   = 12 / 170                             // since 1 ticket is already drawn

Probability that Garrett will win Third   = tickets he purchased / total number of tickets left  

Probability that Garrett will win Third   = 12 / 169

Overall Probability = Product of all Probabilities

                            = (12/171) * (12/170) * (12/169)

                            = 1728 / 4912830

                            = 96 / 272935           

             option    (b)