Calculate the molarity of a NaOH solution if 3202mL of the s

Calculate the molarity of a NaOH solution if 32.02mL of the solution neutralizes 0.2262g of oxalic acid dihydrate. show steps

Solution

Molar mass of H2C2O4.2H2O ,
MM = 6*MM(H) + 2*MM(C) + 6*MM(O)
= 6*1.008 + 2*12.01 + 6*16.0
= 126.068 g/mol


mass(H2C2O4.2H2O)= 0.2262 g

use:
number of mol of H2C2O4.2H2O ,
n = mass of H2C2O4.2H2O /molar mass of H2C2O4.2H2O
=(0.2262 g)/(126.068 g/mol)
= 1.794*10^-3 mol

The balanced chemical reaction is:
H2C2O4.2H2O + 2NaOH Na2C2O4 + 4H2O

mol of NaOH required = 2*moles of H2C2O4.2H2O
= 2*1.794*10^-3 mol
= 3.588*10^-3 mol

now use:
mol = M*V
3.588*10^-3 mol = M * 0.03202 L
M = 0.112 M

Answer: 0.112 M