For this problem use your initial population of N8000 with a

For this problem use your initial population of N=8,000 with an allele frequency of 0.3 for the A1 allele (p) from #1d and e. Now consider a group of 3,000 migrants with 0.8 as the allele frequency (p) for the A1 allele. Assuming random mating among this group of migrants and the resident population, what will be the frequency (p) of the A1 allele? What will be the frequency (q) of the A2 allele? Show your calculations and results. Keep 4 significant digits after the decimal. Using a Punnett square determine genotype frequencies after migration. Show your calculations and results. Keep 4 significant digits after the decimal.

Solution

Q. 2c.Let us consider the resident population first. Here, the proportion of allele A1 is 0.3 x 8000 (allele frequency x N)

= 2400 A1

Likewise, the proportion of allele A1 in the migrant population = 0.8 x 3000 = 2400

Now, the resident population and the migrant population undergo random mating according to the Hardy-Wienberg equilibrium.

The resulting proportion of A1 allele = 2400 + 2400

= 4800

Frequency of A1 allele (p) in the final population = 4800/11000 = 0.4364

Therefore, frequency of A2 allele (q) in the final population = 1 - 0.4364

= 0.5636

Q. 2d. Genotype frequency using Punnet square approach

Gametes
Male	Female	Genotype frequency
(p = 0.4364) 0.4364 A1	(p = 0.4364) 0.4364 A1	p2 =0.1904 A1A1 pq= 0.2459 A1A2
(q = 0.5636) 0.5636 A2	(q = 0.5636) 0.5636 A2	pq= 0.2459 A1A2 q2 = 0.3176 A2A2