Name Prablem 2020 points kiiven the following below Solution

Name Prablem 2020 points kiiven the following below

Solution

f(x)= sqrt(x+4) , g(x)=x²

fog(x)= f(g(x))=f(x²) = sqrt(x²+4)

gof(x) = g(f(x))=g(sqrt(x+4)) = x+4

fog(x) not equal to gof(x)

Domain of fog(x)

Here there is no restriction on x of g(x). Therefore domain is (-infinity,infinity)