4xy5 yz0 6xz6 x y zSolutionGiven 4x y 5 equation 1 y z

4x+y=5

y+z=0

6xz=6

Given,

4x + y = 5 ------------ (equation 1)

y + z = 0 ------------- (equation 2)

6x z = 6. ------------- (equation 3)

From equation 2, we have y = - z.

Substituting \'y\' as \'-z\' in equation 1, it becomes,

4x + y = 5

4x + (-z) = 5

That is, 4x - z = 5

Equation 3 is, 6x z = 6

Subtracting, ---------------------

-2x + 0 = -1

------------------------

So we have, -2x = -1

Dividing both sides by -2, we have, x = (-1)/(-2)

That is, x = 1/2

Plugging in x as 1/2 in equation 1, \"4x + y = 5\" becomes,

4(1/2) + y = 5

2 + y = 5

y = 5 - 2 = 3

Hence, y = 3

From equation 2, we already have \"y = - z\"

So we can see, \"z = -3\"

Hence, x = 1/2, y = 3, z = - 3.