Given A is a subset of RdSolutionSuppose x0 is one of the li
Given A is a subset of Rd.
Solution
Suppose x0 is one of the limit points of A, then for any given epsilon, we can find x in A\' such that |x-x0|<epsilon/2.
Now x becomes another limit point of A abd hence there is one x1 in A\' such that |x1-x|<epsilon/2
Hence |x1-x0|<epsilon.
Hence x0 is a limit point of A and is contained in A\'.
But A\' contains all limit points.
It follows that
A\' = set of limit points of closure of A
