The answer is correct but I need worked solution for this pr

The answer is correct but I need worked solution for this problem.

the enn mit bet ar ust C k/ m bo m081 9 s5b ioo 0us t5ee 0 0 -fro se c94119 n a ri is 0-11-9 re or hi 2. 4-3-0-1 vici

0.610 gm Titanium = mass / molar mass = 0.610 / 47.867 = 0.0127 mole.

Heat = heat capacity * temperature change = 9.84 * (323.5 - 298.0) = 250.92 KJ

Heat of reaction for combustion of one mole Ti = 250.92 / 0.0127 = 1.98 * 10^-4 KJ / mol

as during combustion of reaction heat is released, so the answer is -1.98*10^-4