QUESTION 6 The equilibrium constant is given for two of the

QUESTION 6 The equilibrium constant is given for two of the reactions below. Determine the value of the missing equilibrium constant A (g) + 2 B (g) AB2 (g) AB2 (g) + B (g) AB3 (g) A (g) + 3 B (g) -AB, (g) Kc = 59 Ko ? K. = 478 Oa, 8.1 b. 0.0811 c. 0.81 od, 81 e.

Solution

A(g) + 2B(g) ---------------> AB2(g)                Kc1 = 59

    Kc1   = [AB2]/[A][B]^2

AB2(g) + B(g) ------------> AB3(g)                   Kc2 =

Kc2   = [AB3]/[AB2][B]

A(g) + 3B(g) ---------------> AB3(g)               Kc3 = 478

      Kc3 = [AB3]/[A][B]^3

   Kc3/Kc1   = [AB3]/[A][B]^3/ [AB2]/[A][B]^2

Kc3/Kc1    = [AB3]/[AB2][B]

Kc3/Kc1   = Kc2

478/59   = Kc2

Kc2   = 8.1

a. 8.1 >>>>>answer