include include using stdcout using stdendl int main int in

#include <iostream>

#include <cstdlib>

using std::cout;

using std::endl;

int main() {

int integer1, * p1, ** p2;

integer1 = 10; // line 11

p1 = &integer1; // line 12

p2 = &p1; // line 13

cout << \"integer1 = \" << integer1 <<endl; // line 15

cout << \"p1 = \" << p1 << endl; // line 16

cout << \"p2 = \" << p2 << endl; // line 17

return EXIT_SUCCESS;

} // main

Suppose after the declaration of variables integer1, p1, and p2, we have the following memory map:

(a) Fill in the “Value” column in the in the memory map to reflect the changes that are caused by lines 11, 12, and 13.

(b) If we substitute lines 15–17 with the the following two statements, then what will be the output of the program?

(*p1)++;

cout << \"integer1 = \" << *p1 << endl;

integer1++;

cout << \"integer1 = \" << *p1 << endl;

(d) Will the output of the program be the same if we substitute the above two lines with the following two statements?

*p2++;

cout << \"integer1 = \" << integer1 << endl;

(e) Explain why the outputs of parts (c) and (d) are the same or different from each other.

Consider the following program and answer the questions below:

#include <iostream>

#include <cstdlib>

int main() {

int * p1;

int ** p2;

p2 = p1;

return EXIT_SUCCESS;

} // main

(a) What does the variable p2 represent?

(b) Will this program compile? Why or why not?

Symbol Name Type Memory Address Value integeri int 80 p1 int 84 p2 int 92

A>P2 presents with null value we are assigning P1 value to p2 but p1 contains null value.so we wont assign null value to another integer parameter

B>Program will complie successfully but it gives runtime error like null value we can\'t assign to another parameter