a What is the de Broglie wavelength of a helium nucleus with

a. What is the de Broglie wavelength of a helium nucleus with an energy of 0.001 eV?

b. What is the de Broglie wavelength of a 45 g golf ball traveling at 10 mph?

a. De- broglie wavelenth,

E = h c / lambda

hc = 1240 eV - nm

0.001 eV = 1240 ev -nm / lambda

lambda = 1.24 x 10^6 nm = 1.24 x 10^-3 m Or 1.24 mm

(B) wavelength, lambda = h / p

p = m v

m = 45 x 10^-3 kg

v = 10 mph = 10 x 1609 m / 3600s = 4.47 m/s

= (6.626 x 10^-34) / (45x 10^-3) (4.47)

= 3.29 x 10^-33 m