Im confused by this question Find the enthalpy change in the

Im confused by this question.

Find the enthalpy change in the following reaction.

NaHCO3(s) + HCl(aq) → NaCl(aq) + H2O(l) + CO2(g)

Solution

NaHCO3 (s) + HCl (aq) → Nacl (aq) + H2O (l) + CO2 (g) ∆H= +32.3 KJ/mol

from info

NaHCO3 (s) + (aq) → NaHCO3 (aq) ∆H = +17.6 KJ/mol

NaOH (aq) + HCl (aq) → NaCl (aq) +H2O (l) ∆H= -70.2 KJ/mol