Show that if a b element Z and c element N such that a Ident
Show that if a, b element Z, and c element N such that a Identical b (mod c), then gcd (a, c) = gcd(b, c).
Solution
a=b mod c
hence, a-b|c
a-b=kc where k is some integer
Let, gcd(a,c)=p, gcd(b,c)=q
So , a=pm,c=pn
pm-b=kpn
Hence, p|b and p|c
But, q is gcd(b,c) hence, q|p
Similarly we can show:p|q
Hence, p=q
HEnce proved
