In how many ways can 12 indistinguishable apples and 1 orang
Solution
Case 1. Orange is given to some child
Choose 1 child out of three in C(3,1)=3 ways.
Apple is given to other two in 1 way.
Now there are 10 more apples to which can be distributed to each kid given 0 or more apples
The number of ways of distributing n identical objects among r groups such that each group can have 0 or more objects <=n
is: C(n+r-1,r-1)
Hence number of ways of giving n=10 apples to r=3 children where each can get 0 or more apples is
C(10+3-1,3-1)=C(12,2)=12*11/2=66
So total number of ways is: 66*3=198
Case 2. All get only apples
First we give an apple to each children
Now we have 9 apples:n=9 and r=3 children and each can get 0 or more apples. So number of ways to distribute are:L
C(9+3-1,3-1)=C(11,2)=55
So ,55 ways.
So total ways to distribute are:
198+55=253
