K has exist160 J has 14 as much as k and D has 12 as much as

K has exist160, J has 1/4 as much as k, and D has 1/2 as much as K and J together. Altogether they have: exist300 exist460 exist360 exist440 exist400

Solution

K = 160

J = 160*(1/4) = 40

D = (160 + 40)* (1/2)

= 200*(1/2)

= 100

Altogether they have = 160 + 40 + 100 = 300

Option - A $300