Com Parebe t w een the domainofHae un 123x then Com Pare th

Com Pare-be t w een the -domain-of-Hae.- un 12-3x , then Com Pare the dem.a

Solution

f(x) = sqrt(12-3x)

Square root cant be negative

12-3x>=0

x <=4

(-infinity,4]

g(x) = 1/sqrt(12-3x)

Denominator should not be zero and square root cant be negative

12-3x>0

x<4

(-infinity,4)

(f.g)(x) = sqrt(12-3x) * 1/sqrt(12-3x) =1

Domain includes the domain of both functions

Therefore domain = (-infinity,4)

(f/g)x = sqrt(12-3x)/(1/sqrt(12-3x) =12-3x

Again domain of (f/g) depends on both functions

So domain =(-infinity,4)

 Com Pare-be t w een the -domain-of-Hae.- un 12-3x , then Com Pare the dem.a Solutionf(x) = sqrt(12-3x) Square root cant be negative 12-3x>=0 x <=4 (-infi

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