V Solution The graph is that of a parabola opening upwards

V

Solution

The graph is that of a parabola opening upwards , with vertex at (0,-4).It passes through the point (2,0). Let its equation be y = a(x-0)2 - 4 = ax2 - 4. Since the parabola passes through the point (2,0), on substituting x = 2,y= 0 in its equation, we get 0 =a*4 -4 or, 4a - 4 = 0 so that a = 1. Then, the equation of the parabola is y = x2 -4. The image is faint, so the answer is on a best effort basis. The graph is that of a parabola opening upwards , with vertex at (-3,-2).It appears to be passing through the point (-1,2). Let its equation be y = a(x+3)2 -2. Since the parabola passes through the point (-1,2), on substituting x = -1,y= 2 in its equation, we get 2 =a*(-1+3)2 -2 or, 4a - 2 = 2 so that a = 1. Then, the equation of the parabola is y = (x+3)2 -2. The graph is that of a parabola opening upwards , with vertex at (-1,-2).It appears to be passing through the point (1,2). Let its equation be y = a(x+1)2 -2. Since the parabola passes through the point (1,2), on substituting x = 1,y= 2 in its equation, we get 2 =a*(1+1)2 -2 or, 4a - 2 = 2 so that a = 1. Then, the equation of the parabola is y = (x+1)2 -2.