Evaluate the limit limx rightarrow 0 5x2 2sin2 x21 x2 Solut
Evaluate the limit: lim_x rightarrow 0 5x^2 + 2sin^2 x/21 x^2
Solution
limx -> 0 ( 5 x2 + 2sin 2x )/ 21 x 2 { limx -> 0 ( sin x )/x = 1 }
= limx -> 0 (5 x2/21 x 2 ) + (2sin 2x / 21 x 2)
{limx -> 0 ( sin2 x )/x2 = 1 & since both limit exists we can add both these}
= limx -> 0 5 /21 + 2 /21
= 7 /21 = 1 /3
