An ion having charge 6e is traveling horizontally to the lef

An ion having charge +6e is traveling horizontally to the left at 8.45 km/s when it enters a magnetic field that is perpendicular to its velocity and deflects it downward with an initial magnetic force of 7.04×1015 N .

What is the direction of this field?

The field is directed to the left.

What is the magnitude of this field? (T)

The field is directed out of the screen.
The field is directed into the screen.
The field is directed to the right.

The field is directed to the left.

Solution

Here,

speed of ion, v = 8450 m/s

Force , F = 7.04 *10^-15 N

as

F = q * V X B

downwards = q * left X B

Using right hand rule

the field is INTO the screen

------------------------------

Now, magnetic field is B

7.04 *10^-15 = 6 * 1.602 *10^-19 * 8450 * B

B = 0.87 T

the magnitude of this field is 0.87 T

An ion having charge +6e is traveling horizontally to the left at 8.45 km/s when it enters a magnetic field that is perpendicular to its velocity and deflects i

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