An ion having charge 6e is traveling horizontally to the lef
An ion having charge +6e is traveling horizontally to the left at 8.45 km/s when it enters a magnetic field that is perpendicular to its velocity and deflects it downward with an initial magnetic force of 7.04×1015 N .
What is the direction of this field?
The field is directed to the left.
What is the magnitude of this field? (T)
| The field is directed out of the screen. |
| The field is directed into the screen. |
| The field is directed to the right. |
| The field is directed to the left. |
Solution
Here,
speed of ion, v = 8450 m/s
Force , F = 7.04 *10^-15 N
as
F = q * V X B
downwards = q * left X B
Using right hand rule
the field is INTO the screen
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Now, magnetic field is B
7.04 *10^-15 = 6 * 1.602 *10^-19 * 8450 * B
B = 0.87 T
the magnitude of this field is 0.87 T
