The nonvolatile nonelectrolyte chlorophyll C55H72MgN4O5 8935

The nonvolatile, nonelectrolyte chlorophyll, C₅₅H₇₂MgN₄O₅ (893.50 g/mol), is soluble in diethyl ether CH₃CH₂OCH₂CH₃.

Calculate the osmotic pressure generated when 13.3 grams of chlorophyll are dissolved in 198 ml of a diethyl ether solution at 298 K.


The molarity of the solution is  M.

The osmotic pressure of the solution is  atmospheres.

Solution

P = i x M x R xT is formula

where P is osmotic pressure , i = vantoff factor = 1 for non electrolyte

R is gas constat = 0.08206 Latm/molK , T = 298 K

moles of chlorophyll = mass / Molar mass of chlorophyll = ( 13.3g / ( 83.5g/mol) = 0.014885

volume of solution = 198 ml = 0.198 L

Molarity = moles of solute / solution volume in L = ( 0.014885 mol) / ( 0.198L) = 0.0752 M

now P = 1 x 0.0752 mol/L x 0.08206Latm/molK x 298 K

P = 1.84 atm