An investor has $24,000 to invest in bonds of AAA and B qualities. The AAA bonds yield an average of 6%, and the B bonds yield 10%. The investor requires that at least three times as much money should be invested in AAA bonds as in B bonds. How much should be invested in each type of bond to maximize the return? What is the maximum return? Enrolments in finite math class are Find number of elements n for: A small combination lock has 3 wheels, each labeled with the 10 digits from 0 to 9. How many 3-digit combinations are possible if no digit is repeated? If digits can be repeated? If successive digits must be different? A small combination lock has 3 wheels, each labeled with the 10 digits from 0 to 9. If an opening combination is a particular sequence 3 digits with no repeats, what is the probability of a person guessing the right combination? Because of limited funds, 5 research centers are chosen out of 8 suitable ones for a study on heart disease. How many choices are possible? In how many different ways can 6 candidates for an office be listed on a ballot? Two balls are drawn in succession w/o replacement, from a box containing 2 red and 5 white boards. Construct probability tree for this experiment and find the probability of drawing red ball on the second draw. Find the mean, median, mode and standard deviation for the following set of ungrouped sample data {1, 2, 2, 3}. Guarantees. The average lifetime for a car battery is 170 weeks, with a standard deviation of 10 weeks. If the company guarantees the battery for 3 years, what percentage of the batteries sold would be expected to be returned before the end of the warranty period? Assume a normal distribution.
2.
n(S) = 14 + 21 = 35
n(B) = 66 + 21 = 87
n(AnF) = 19
n(BnS) = 21
n(AUF) = n(A) + n(F) - n(AnF)
= (19 + 14) + (19 + 66) - 19 = 99
3.
If no digit is repeated = ABC
total case to choose digit A = 10C1 = 10 (from 0 to 9 total 10 digits possible)
total case to choose digit B = 9C1 = 9 (from 0 to 9 total 9 digits possible, as 1 digit is taken by place A)
total case to choose digit B = 8C1 = 8 (from 0 to 9 total 8 digits possible, as 2 digits are taken by place A and B)
Total combination = 10*9*8 = 720
if digits can be repeated = ABC
total case to choose digit A = 10C1 = 10 (from 0 to 9 total 10 digits possible)
total case to choose digit B = 10C1 = 10 (from 0 to 9 total 10 digits possible)
total case to choose digit C = 10C1 = 10 (from 0 to 9 total 10 digits possible)
Total combination = 10*10*10 = 1000
if successive digits must be different = ABC
total case to choose digit A = 10C1 = 10 (from 0 to 9 total 10 digits possible)
total case to choose digit B = 9C1 = 9 (from 0 to 9 total 10 digits possible, one digit is taken by A)
total case to choose digit C = 9C1 = 9 (from 0 to 9 total 10 digits possible, one digit is taken by B)
Total combination = 10*10*9 = 900
4.
Probability = total correctcombination/total possible combination
P(Correct) = 1/720
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