A rigid tank contains helium molar mass M 4 kgkgmol at 60 k

A rigid tank contains helium (molar mass, M = 4 kg/kg_mol) at 60 kPa and 40 degree C. One kg of the gas is removed, which causes the pressure and temperature to change to 340 kPa and 90 degree C find (a) the original mass in the tank, in kg and (b) the volume of the tank, in m^4 kPa.m^3/kg_mol. K.

Solution

Here ,

a) let the original mass of the gas in the chamber is m

let the volume of the tank is V

NOw , as P1/(n1 * T1) = P2/(n2 * T2)

600/(m * (40 + 273)) = 340/((m - 1) * (20 + 273))

solving for m

m = 2.54 Kg

the original mass of the gas is 2.54 Kg

b)

Using ideal gas equation

P * V = n * R* T

600 * 10^3 * V = (2540/4) * 8.314 * (40 + 273)

solving for V

V = 2.75 m^3

the volume of the tank is 2.75 m^3