Find the sum of 35n2n from n1 to infinity Im trying to chang

Find the sum of (3/(5^n))+(2/n) from n=1 to infinity.

I\'m trying to change the expression to get it under one power so I can use the a/(1-r) equation to find the sum if convergent. But I can\'t! I know the answer is divergent but I would like to find out why and if it is possible to get the expression raised to one power. Please help. Thank you :)

The sum is > sum (2/n) from 1 to infinity which is 2 times the harmonic series, which is divergent. Hence, the original series is also divergent.

sum(3/5^n + 2/n) sum(2/n) = infinity (harmonic series)

$Find the sum of (3/(5^n))+(2/n) from n=1 to infinity. I\'m trying to change the expression to get it under one power so I can use the a/(1-r) equation to find t$

Find the sum of 35n2n from n1 to infinity Im trying to chang

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