Homework SourseThe rate constant for the reaction is 0840 MSolutionUse Equa
The rate constant for the reaction is 0.840 M^(
Solution
Use Equation: 1/[A]t - 1/[A]o = K t
[A]o = 0.00340 M
K = slope of line = 0.840
t = 125 s
therefore,
1/[A]t - 1/[.00340] = (0.840) * (125s)
1/[A]t - 1/[.250] = 105
1/[A]t =400
1/[A]t =400
[A]t = 0.0025 M
![The rate constant for the reaction is 0.840 M^(SolutionUse Equation: 1/[A]t - 1/[A]o = K t [A]o = 0.00340 M K = slope of line = 0.840 t = 125 s therefore, 1/[A]](/WebImages/33/the-rate-constant-for-the-reaction-is-0840-msolutionuse-equa-1097433-1761579089-0.webp "The rate constant for the reaction is 0.840 M^(SolutionUse Equation: 1/[A]t - 1/[A]o = K t [A]o = 0.00340 M K = slope of line = 0.840 t = 125 s therefore, 1/[A]")
