Problem 8 Prove or give a counterexample to each of the foll
Solution
Ans(1):
we know that adding opposite of a number to itself will always give 0 and to get greater than 0 value we can add any positive integer so choosing y=-x+1 will always satisfy the given statement
x+y=x-x+1=1 which is clearly >0
Hence it is true for all cases.
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Ans(2):
we know that subtracting a number from itself will always give 0 and to get greater than 0 value we can add any positive integer so choosing y=x-1 will always satisfy the given statement
x-y=x-(x-1)=x-x+1=1 which is clearly >0
hence it is True.
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Ans(3):
It is False because for some given x, x+y will not always be >0 for all y in R
like say x=2 and y=-5
then x+y=2-5=-3 which is clearly not >0
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Ans(4):
it will fail for x=0
as we know product of 0 with any real number is again 0
while condition xy>0 doesn\'t include 0
hence it is False
