2 cos X 1 0 pi6 2n pi 5 pi6 2n pi pi3 2n pi 5 pi3 2n p
2 cos X - 1 = 0 pi/6 + 2n pi: 5 pi/6 + 2n pi pi/3 + 2n pi: 5 pi/3 + 2n pi pi/4 + 2n pi: 5 pi/4 + 2n pi 2 pi/3 + 2n pi: 4 pi/3 + 2n pi
Solution
2 cosx - 1 = 0
adding 1 on both sides
2 cos x = 1
dividing both sides by 2
cos x = 1/2
x = cos ^-1 ( 1/2 )
x = pi/3 + 2pi*n , 5pi/3 + 2pi*n
option b is correct
