Find the standard form of the circle with a diameter that ha
Find the standard form of the circle with a diameter that has end points (-7,-5) and (9,5)
h= k= r=
Solution
Solution:
Center of the circle (h,k) = mid point of the end points given
=> (h,k) = ( (-7+9)/ 2 , (-5+5)/ 2
=> (h,k) = (1,0)
and radius will be the distance between this point(center) and any of the given end points.
=> radius = r = (1-(-7))2 +(0-(-5))2
=> r = 64+25
=> r =89 = 9.434 units
hence;
standard form:
(x-1)2+(y-0)2 = 89
