thanks 1propanol P1 degree 209 Torr at 25 degree C and 2pro

thanks

1-propanol (P1 degree = 20.9 Torr at 25 degree C) and 2-propanol (P2 degree = 45.2 Torr at 25 degree C) form ideal solutions In all proportions. Let Times 1 and Times 2 represent the mole fractions of 1-propanol and 2-propanol In a liquid mixture, respectively, and y1 and y2 represent the mole fractions of each In the vapor phase. For a solution of these liquids with x1 = 0.770, calculate the composition of the vapor phase at 25 degree C.

Solution

p1=P1o*X1=16.093

p2=P2o*X2=10.396

Y1=16.093/(16.093+10.396)=0.60753

Y2=0.39246