Question 6 1 pts Calculate the pH after 260 mL of 038 M LiOH

Question 6 1 pts Calculate the pH after 26.0 mL of 0.38 M LiOH was added to 23.0 mL of 0.33 M C&Hs; Ka of C&HsCOOH; is 1.8 x 105 O 10.28 O 8.35 O 3.44 O 12.67 O 1.33

Solution

Let the acid be HA

LiOH + HA -------------------> LiA + H2O

26x0.38= 9.88 23x0.33=7.59 0 0 initial mmoles

2.29 0 7.59 - after reaction

Thus sthe solution has a strong base and salt. So the pH is calculated as

pH = 14-pOH

pOH = - log [OH-]

[OH-] in the mixture = mmoles/ total volume

= 2.29/49

=0.04673 M

Thus pOH = - log 0.04673

= 1.33

and pH of the solution = 14 -1.33

= 12.67