Show that there are at least two values of x in the interval

Show that there are at least two values of x in the interval (-pi, pi) such that x = 1 + sin(x).

Solution

x=1+sinx

We can break this equation in

y=x and y=1+sinx

And the x coordinates of the intersection point are the required solutions

As we see that the two graph intersects at only x=1.935 and that\'s the only solution